NetNews Offline 2/NetNews Offline Volume 2.iso/news/comp/lang/c-part1/2882

Internet Message Format | 1996-08-05 | 1.7 KB

Path: mail2news.demon.co.uk!genesis.demon.co.uk
From: Lawrence Kirby <[e-mail]>
Newsgroups: comp.lang.c
Subject: Re: why get 9 strings only?
Date: Wed, 24 Jan 96 17:25:37 GMT
Organization: none
Message-ID: <[e-mail]>
References: <4e51th$[e-mail]> <4e5km4$[e-mail]>
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In article <4e5km4$[e-mail]> [e-mail] "John R Buchan" writes:

>In article <4e51th$[e-mail]>, [e-mail] says...
>>
>>I can't figure out why I can only input 9 strings
>>instead of 10 on the following program:

>>{
>>        char str[10][80];
>>        int i, j;
>>
>>        printf("Enter a number (0-9):\n");
>>        scanf("%d", &j);
>
>Using scanf for input to input numeric values is tricky.  Here you've
>told it to read an integer value and store it in j.  It obediently
>reads chars until it reaches the first one that isn't allowed for ints.
>In this case probably a '\n'.  It leaves the unused char in the buffer,
>converts the read chars, and stores the value in j.

That's one problem.

...

>>
>>        if(j>0 && j<10)
>>                printf("Answer: %s\n", str[j]);
>>}

This only allows you to select indices between 1 and 9 i.e. 9 values. To
see the first one you need to make the first test j>=0. Couples with the
first problem this makes it look like it reads only the first 9 lines
and indexes the first line from 1 rather than 0.

--
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Lawrence Kirby | [e-mail]
Wilts, England | [e-mail]
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